# Project Euler #99

Hence, to simplify calculations I did some algebraic manipulations, using logarithms. Take two exponents such that $a^b > c^d$. For all $a,b\geq0$, we can take the natural log of both sides and not change the equation (the sign to be specific), resulting in – $b\log(a) > d\log(c)$. We already know that our assumption about a and b is true for the given data, thus, we can continue to calculate the product of the exponent part and the natural log of the base of each number. For whichever datum this is the greatest, is in turn the greatest number of the lot.